Question 76400
Since 9! is 9*8*7*6*5*4*3*2*1 and 4! is 4*3*2*1 we have a common factor of 4*3*2*1 . So we can factor this out

{{{4*3*2*1(9*8*7*6*5+1)}}}
{{{24(15120+1)}}} Compute the factorials
{{{24(15121)}}} Add
{{{24(15121)}}}
{{{362904}}}

This is just one way of doing it. You can just simply evaluate 9! and 4! and add the 2 large numbers together, but I thought I'd show you another way.