Question 903474
{{{f(z)=5-2z^2}}}
Substitute the value for {{{z}}}.
{{{f(-2)=5-2(-2)^2}}}
{{{f(-2)=5-2*4}}}
{{{f(-2)=5-8}}}
{{{f(-2)=-3}}}
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{{{f(0)=5-2(0)^2}}}
{{{f(0)=5-2*0}}}
{{{f(0)=5-0}}}
{{{f(0)=5}}}