Question 76391
Solve for x:
{{{1+3log(x) = log(x)+log(x)^3}}} Apply the law of exponents for logarithms to the left-hand side.
{{{1+log(x)^3 = log(x)+log(x)^3}}} Subtract {{{log(x)^3}}} from both sides.
{{{1 = log(x)}}} Rewrite the this in exponential form.
{{{x = 10^1}}}
Solution:
x = 10