Question 903394
(y = x +3
(y = - 2x - 3


Find the x & y intercept points by plugging x=0,y=0 in both equations.								
equation I  y = x +3								
when x=	0	y=	3	,(	0	,	3	)
when y =	0	x=	3	,(	-3	,	0	)
Equation 2	y = - 2x - 3
							
when x=	0	y=	-3	(	0	,	-3	)
when y =	0	x=	-1.5	(	-1.5	,	0	)
								
{{{drawing(300,300,-10,10,-10,10,grid(1),circle(0,3,0.3),circle(-3,0,0.3),circle(0,-3,0.3),circle(-1.5,0,0.3),graph(300,300,-10,10,-10,10,y=-2x-3,y=x+3))}}}								
								
You will observe that the point of intersection is						-2	,	1
The solution of the system is			(  	-2	,	1	)