Question 903323
Find the remaining trigonometric ratios of theta if cos theta = -1/3 and theta is not in QII 
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cos<0 in QII and QIII, so it must be in QIII for this problem
cos theta=-1/3
sin theta=&#8730;(1-cos^2 theta)=&#8730;(1-(-1/3)^2)=&#8730;(1-(1/9))=&#8730;(8/9)=&#8730;8/3=2&#8730;2/3
tan theta=sin theta/cos theta=-2&#8730;2
sec theta=-3
csc theta=3&#8730;2/4
cot theta=-&#8730;2/4