Question 903357
x+y=12000,
.09x=.11y

x=6600.,   y=5400.We know the total amount of money invested. $12000
x+y=12000,
We know that the difference in  the two accounts is $0
0.09*x-0.11*y=0
x=12000-y
We substitute for x
0.09*(12000-y)-0.11*y=0
We multiply out
1080-0.09y-0.11*y=0
We combine like terms.
1080=0.2*y
Isolate y
y=5400 at 11%
Calculate x
x=12000-5400
x=6600 at 9%
We check
0.09*6600-0.11*5400=0
594-594=0
0=0
Since this statement is TRUE and neither amount is negative then it is ok