Question 10324
{{{(2+3i)^3 = (2+3i)(2+3i)(2+3i)}}}  Multiply the first pair of parentheses.

{{{(2+3i)(2+3i) = (4+6i+6i+9i^2)}}} But, {{{i^2 = -1}}}

{{{(2+3i)(2+3i) = 4+12i+9(-1))}}} = {{{4+12i-9 = -5+12i}}} Now multiply this by (2+3i)

{{{(-5+12i)(2+3i) = -10-15i+24i+36i^2}}} Simplify.

{{{(2+3i)^3 = -46+9i}}}