Question 76371
<pre>
Find two consecutive intergers such that twice the first interger plus the second interger equals 46.


What is asked in the problem?

  find two consecutive integers

Given:

  twice the first plus the second integer equals 46

Representation:
Let     n be the first integer
    n + 1 be the second integer 

Equation:
   2n + n + 1 = 46                combine like terms
       3n + 1 = 46                Subtract 1 both sides 
           3n = 45                divide 3 both sides  
            n = 15  First integer

  n + 1 = 15 + 1
        = 16        Second integer


CHecking :

   2(15) + 16 = 46
     30  + 16 = 46
           46 = 46  ----> True


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