Question 902821
1.{{{A*B=540}}}
2.{{{A/B=15}}}
From eq. 2,
{{{A=15B}}}
Substituting into eq. 1,
{{{15B*B=540}}}
{{{B^2=36}}}
{{{B=6}}} or {{{B=-6}}}
Then,
{{{A=15(6)}}} or {{{A=15(-6)}}}
{{{A=90}}} or {{{A=-90}}}
So then numbers are either, {{{6}}} and {{{90}}}, or {{{-6}}} and {{{-90}}}.