Question 903018
Let North be positive {{{y}}}, let East be positive {{{x}}}.
You're at ({{{0}}},{{{0}}}).
Draw a circle of radius {{{10}}}.
Draw a circle of radius {{{12.36}}}.
The first point is ({{{0}}},{{{10}}}) since it only has a North ({{{y}}}) component.
To find the second point, build a right triangle starting at ({{{0}}},{{{0}}}) with a hypotenuse that is {{{17.4}}} degrees from the {{{y}}} axis (East or positive {{{x}}} direction). 
You can then calculate the leg lengths using the angle and the hypotenuse.
X leg : {{{12.36*sin(17.4)=3.69}}
Y leg : {{{12.36*cos(17.4)=11.79}}}
The second point is (3.69,11.79)
{{{drawing(300,300,-8,8,-2,14,grid(1),circle(0,0,10),circle(0,0,12.36),line(0,0,0,11.8),line(0,11.8,3.7,11.8),blue(line(0,0,3.7,11.8)))}}}
To calculate the distance between two points, use the distance formula,
{{{D^2=(3.69-0)^2+(11.79-10)^2}}}
{{{D^2=3.69^2+1.79^2}}}
{{{D^2=16.820}}}
{{{D=4.1}}}{{{km}}}