Question 551349
{{{1/x + 1/(x+2) = 1/8}}} 
Multiply by 8x(x+2) to remove denominators
 8(x+2) + 8x = x(x+2)
x^2 -14x - 16 = 0 
(Reject the negative solution for time)
 *[invoke quadratic "x", 1, -14, -16] 
*[invoke complete_square "x", 1, -14, -16]