Question 902992
{{{(30u^(-15))/(34u^(-16))=(30/34)u^(-15-(-16))}}}
{{{(30u^(-15))/(34u^(-16))=(15/17)u^(-15+16)}}}
{{{(30u^(-15))/(34u^(-16))=(15/17)u^(1)}}}
{{{(30u^(-15))/(34u^(-16))=(15/17)u}}}