Question 76292
simplify 
3i - 2i^2 + 3 
DIvided by 
the square root of -16 - the square root of -2 times the square root of -2
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[3i -2i^2 + 3]/[sqrt(-16) -(sqrt(-2)*sqrt(-2))]

=[3i + 2 + 3]/[4i -(isqrt(2))^2]

=[3i+5]/[4i - (-2)]

=[5+3i]/[2+4i]
Multiply numerator and denominator by 2-4i to get:

=(5+3i)(2-4i)/20

=(22-14i)/20

=(11-7i)/10

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Cheers,
Stan H.