Question 76288
{{{ Z(Z+27)=5(3Z-7) }}}
First you must distribute the z and the 5 across their quantities.
{{{ z^2 + 27z = 15z - 35 }}}
Move all values to the left, thereby setting the equation equal to zero.
{{{ z^2 + 27z - 15z + 35 = 0 }}}
Combine like terms
{{{ z^2 + 12z + 35 = 0 }}}
Factor
{{{ (z+5)(z+7) = 0 }}}
Set each piece equal to zero
{{{ z+5=0 }}} and {{{ z+7=0 }}}
{{{ z=-5 }}} and {{{ z=-7 }}}