Question 902512
We know the total amount of money invested. $10000
x+y=10000,
We know that the total interest for the year for the two accounts is $760
0.06*x+0.1*y=760
x=10000-y
We substitute for x
0.06*(10000-y)+0.1*y=760
We multiply out
600-0.06y+0.1*y=760
We combine like terms.
0.04*y=160
Isolate y
y=4000 at 10%
x=10000-y
Calculate x
x=6000 at 6%
We check
0.06*6000+0.1*4000=760
360+400=760
760=760