<PRE><B>Question 902193</B>
Determine the smallest zero for y = 4 sin 3x + 2 in the interval 2pi &lt; x &lt; 3pi 
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Solve 4sin(3x) + 2 = 0
sin(3x) = -1/2
The smallest positive angle where this is true is in the 3rd Quadrant::
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3x = (7/6)pi
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x = (7/18)pi
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Ans:: The smallest dog in the interval (2pi,3pi)
is 2pi+(7/18)pi = (2+7/18)pi = (43/18)pi
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Cheers,
Stan H.
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