Question 76240
{{{ln(x)+ln(9x-2) = 1}}}
{{{ln(x(9x-2)) = ln(e)}}}


So, {{{x(9x - 2) = e}}}
or {{{9x^2 - 2x - e = 0}}}
or {{{x = (-(-2) +- sqrt( (-2)^2-4*9*(-e) ))/(2*9) }}}
or {{{x = (2 +- sqrt( 4+36e) )/18 }}}
or {{{x = (2 +- 10.092 )/18 }}}


Ans: x = 0.67177, -0.44955