Question 76245
<pre><font size = 4><b>
{{{(3x^2 -4xy -5y^2)^2}}}

Learn the rule:

The square of the sum of any number of terms =

       The sum of all the squares of the terms +  
    
              The sum of TWICE THE PRODUCT of every possible pair of terms. 
       
When there are three terms:

{{{(A + B + C)^2 = A^2 + B^2 + C^2 + 2AB + 2AC + 2BC}}}

So your problem is:

{{{(3x^2 - 4xy - 5y^2)^2}}} = 

{{{(3x^2)^2 + (-4xy)^2 + (-5y^2)^2 + 2(3x^2)(-4xy) + 2(3x^2)(-5y^2)+2(-4xy)(-5y^2)}}} =

   {{{9x^4+16x^2y^2+25y^4-24x^3y-30x^2y^2+40xy^3}}}

There are only two like terms to combine, {{{+16x^2y^2}}} and {{{-30x^2y^2}}}

{{{9x^4-14x^2y^2+25y^4-24x^3y+40xy^3}}}

It is customary to arrange the terms is descending order 
of powers of one of the letters, usually the one that 
comes first in the alphabet.  Here it is arranged in 
descending order of powers of x:

{{{9x^4-24x^3y-14x^2y^2+40xy^3+25y^4}}}
 
Edwin</pre>