Question 902100
{{{2/lg(x-4)=1}}}
{{{2=log((x-4))*1}}}
{{{2=log((x-4))}}}
Is the base 10 ?


If it is, then the equivalent exponential form is {{{10^2=x-4}}}
{{{100=x-4}}}
{{{x=100+4}}}
{{{highlight(x=104)}}}


Try to check this.
{{{2/log(10,(104-4))}}}
{{{2/log(10,100)}}}
{{{2/log(10,10^2)}}}
{{{2/(2*log(10,10))}}}
{{{2/(2*1)}}}
{{{1}}}
YES, x=4 works.



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