Question 902003
{{{y}}} to the second power is {{{y^2}}}
if equals to {{{1/49}}}, you write it as an equation like this:

{{{y^2=1/49}}} ...now solve for {{{y}}}


{{{y=  sqrt(1/49)}}}

{{{y=sqrt(1)/sqrt(49)}}}

{{{y= 1/7}}}

solutions:

{{{y= 1/7}}} or {{{y=- 1/7}}}