Question 901870
The diagonal is the hypotenuse and the length and width are the legs .
(20+x)^2+x^2=100^2
2x^2+40 x+400 = 10000
2x^2+40x - 9600=0
*[invoke quadratic_formula 2, 40, -9600, "x"]
We discard negative measurements
x = 60 y=80
The length is 80 the width is 60 and the diagonal is 100