Question 76193
{{{ ((6p-18)/9)/((3p-9)/(p^2+2p)) }}}
With a problem like this (a Complex fraction) remember this rule:
{{{ (a/b)/(c/d) = ad/bc }}}
Apply this to your problem
{{{ (6p-18)(p^2+2p)/9(3p-9) }}}
Factor all pieces
{{{ 6(p-3)p(p+2)/(9*3(p-3)) }}}
Cancel the (p-3) in the numerator and denominator
{{{ 6p(p+2)/(9*3) }}}
Reduce the 6 and the 3
{{{ (2p(p+2))/9 }}}