Question 901424
{{{y=2x^2-8x+9}}}
Complete the square.
{{{y=2(x^2-4x)+9}}}
{{{y=2(x^2-4x+4)+9-2(4)}}}
{{{y=2(x-2)^2+9-8}}}
{{{y=2(x-2)^2+1}}}
The parabola has a vertex at (2,1).
It opens upwards since {{{2>0}}} and its minimum value is {{{y=1}}}.
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{{{graph(300,300,-5,5,-5,5,2x^2-8x+9)}}}