Question 901608
 Prove that (1-cosA) (1-secA) = tan A sinA

I think it should be (1+sec A)

(1-cos A )(1+sec A)

1+secA-cos A -cos A. sec A

1+sec A - cos A-1

1/cos A -cos A

(1-cos^2 A)/ cos A

sin^2 A/cos A

sin A/cos A * sin A
tan A * sin A


2. Prove that secA (1-sinA) (secA+tanA) = 1

sec A-sec A*sin A (sec A+tan A)

(sec a-tan A)(sec A+ tan A)

sec^2A - tan^2A

=1