<PRE><B>Question 901586</B>
one alloy containing 41% aluminum and the other containing 70% aluminum. How many pounds of each alloy must he use to make 50 pounds of a third alloy containing 61%
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Equation:
alum + alum = alum
0.41x + 0.70(50-x) = 0.61*50
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41x + 70*50 - 70x = 61*50
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-29x = -9*50
x = (9/29)50
x = 15.52 lbs (amt of 41% alloy needed)
50-x = 34.48 lbs (amt of 70% alloy needed)
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Cheers,
Stan H.
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