Question 901527
One number is seven less than five times another. If their sum is increased by six, the result is twenty-three. Find the numbers.
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Equations::
x = 5y-7
x+y + 6 = 23
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Substitute for "x" and solve for "y":
5y-7 + y + 6 = 23
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6y -1 = 23
6y = 24
y = 4
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Solve for "x":
x = 5y-7
x = 5*4-7
x = 13
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Cheers,
Stan H.
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