Question 901341
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Hi
Get Your Calculator out
1  P(x&#8804;3) = binomcdf(15000, .002, 3)
   P(x&#8805; 5) = 1- P(x&#8804;4) = 1 - binomcdf(15000, .002, 4)
Find the probability of 1, 2, 3, 4, or 5 accidents
over the same period of time (say five) weeks
2) P(x =1 ) = poissonpdf(2,1)
P(x =1 ) = poissonpdf(2,2)
etc