Question 76085
The given expression is: 


(3x+2)(x-3)= 7x-1


This can be written as:  


3x(x - 3) + 2(x - 3)  = 7x - 1 


==> {{{3x^2 - 9x + 2x - 6 = 7x - 1 }}}


==> {{{3x^2 - 7x - 6 = 7x - 1 }}}


==> {{{3x^2 - 7x - 7x - 6 + 1 = 0 }}}


==> {{{3x^2 - 14x - 5 = 0 }}}


==> {{{3x^2 + 15x - x - 5 =  0}}}


==> {{{3x(x + 5) -1(x + 5) = 0}}} 


==> {{{(3x - 1)(x + 5) = 0}}} 


==> (3x - 1) = 0  OR ( x + 5) = 0 


==> 3x = 1 OR x = -5  


==> x = 1/3  or x = - 5 



Hence, the solution.