<PRE><B>Question 900902</B>
If sine of theta equals -2/3 with theta in quadrant IV, what is cosine of theta?
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By definition, sin = y/r
So, y = -2 and r = 3
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Then x = sqrt[r^2-y^2] = sqrt[9-4] = sqrt(5)
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Ans: cos = x/r = sqrt(5)/3
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Cheers,
Stan H.</PRE>