Question 10280
While I didn't get the picture, I get the picture! (Your diagram didn't show up)

Let's do the aluminium tubing first.

The center pole and the two outer upright poles are 6.5 yds each in length.

The horizontal poles, there are four of them, are 24 ft 8 in. each in length

Adding them all together, making sure that we use common units of measurement, e.g. feet.
Vertical poles:
6.5 yds = 3 ft/yd(6.5 yds) = 19.5 feet But we have 3 of these, so:
3(19.5 ft) = 58.5 feet. 

Horizontal poles:

24 ft 8 inches = 24.67 ft.  But we have 4 of these, so:
4(24.67 ft) = 98.68 feet.

The total length of aluminium tubing then is: 58.5 ft + 98.68 ft = 157.18 feet of tubing.

Now the area of the screening:

We have two rectangles, the dimensions of each one are: 24.67 ft X 19.5 ft.

The area of one of these is: (24.67 ft)(19.5 ft) = 482.065 sq.ft.

So, the two side panels would need 2(482.065) = 962.13 sq.ft. of screening.