Question 900464
Find two integers whose product is 250 such that one of the integers is five less than three times the other integer.
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Equations:
ab = 250
a = 3b-5
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Substitute and solve for "b"::
(3b-5)b = 250
3b^2-5b-250 = 0
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Positive solution::
b = 10
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Solve for "a"::
a = 3b-5 = 25
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Cheers,
Stan H.
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