Question 900411
{{{a^2}}}+{{{b^2}}}={{{c^2}}}
You're give c - the hypotenuse or diagonal - as 6m
You're also given one side as 4m.
Plug in the numbers.
{{{4^2}}}+{{{b^2}}}={{{6^2}}}
16 + {{{b^2}}} = 36
Subtract 16 from each side
{{{b^2}}} = 20
Take the square root of each side
b = roughly 4.47 (rounded)
If you want to be more precise, b=the square root of 20