Question 900350
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Hi
100%-82% = 18%, 18%/2 = 9%, z = invNorm(.09) = -1.341
(100%-9) = 91%,   z = invNorm(.91) = .81859 = 1.341
the Idea is IF z-value is the left or right of the Green Lines...
That is the Critical Area under the Standard Normal Curve for a
two-tailed 82% level of confidence 
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5, exp(-x^2/2)), green(line( -1.341,0, -1.341,exp(- 1.341^2/2)),line(1.341,0,1.341,exp(-1.341^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}