<PRE><B>Question 900095</B>
How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce a mixture that is 50% water?
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Equation:
water + water = water
1*x + 0.40*8 = 0.50(x+8)
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100x + 40*8 = 50x + 50*8
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50x = 10*8
x = 8/5 = 1.6 litres (amt. of pure water to add)
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Cheers,
Stan H.
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