Question 75978
Solve: 5(x-2)^2=3
:
5(x^2 - 4x + 4) = 3
5x^2 - 20x + 20 = 3
5x^2 - 20x + 20 -3 = 0
5x^2 - 20x + 17 = 0
:
No doubt you got to this point in the quadratic formula and had
:
{{{x = (+20 +- sqrt( 60 ))/(10) }}} 
:
:
{{{x = (+20 +- 2*sqrt( 15 ))/(10) }}}
:
:
{{{x = (+10 +- sqrt( 15 ))/(5) }}}; the 2 cancels out here.
:
Otherwise you had it right