Question 899879
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Hi
a. Find the sample mean = 107.1 and the sample standard deviation= 49.1
ME = 1.645(49.1/sqrt(10))
b.  CI: = 107.1 - ME < {{{mu}}} < 107.1 + ME

 = C	z = 1.28155
90%	z =1.645 ****
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576