Question 899413
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Hi
Ho: u &#8805; 500
Ha: u < 500
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t(496) = (496-500)/[8/sqrt(20)] = 4/1.7889 = 2.236
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p-value = P(t> 2.236 when df = 19) = tcdf(2.236,100,19) = .9825
As .9825 > .10,  No, would not conclude mean is <500 
ME = 1.645(8/sqrt(25))
CI: = 496 - ME < {{{mu}}} < 496 + ME