Question 899380
Using DeMoivre's formula,
{{{(0+16i)^(0.25)=(16(cos(90)+isin(90)))^(0.25)
{{{(0+16i)^(0.25)=2(cos(90/4)+isin(90/4))}}}
{{{(0+16i)^(0.25)=2(cos(45/2)+isin(45/2))}}}
{{{(0+16i)^(0.25)=2(0.9238+0.3827i)}}}
{{{(0+16i)^(0.25)=1.848+0.7654i}}}