Question 899382
Perpendicular lines have slopes that are negative reciprocals.
{{{2*m=-1}}}
{{{m=-1/2}}}
Using the point-slope form,
{{{y-7=-(1/2)(x-(-2))}}}
{{{y-7=-(1/2)(x+2)}}}
{{{y-7=-(1/2)x-1}}}
{{{y=-(1/2)x+6}}}
.
.
.
{{{drawing(300,300,-10,10,-10,10,grid(1),circle(-2,7,0.3),graph(300,300,-10,10,-10,10,2x-1/4,-(1/2)x+6))}}}