Question 899010
{{{drawing(300,300,-10,10,-10,10,locate(5,1,x),locate(0.2,3.5,90-x),line(0,0,7,0),line(7,0,0,5),locate(3,0,A),locate(-1,2,B),locate(4,4,H),line(0,5,0,0))}}}
Using this right triangle, by definition,
{{{sin(90-x)=OPP/HYP=A/H}}}
{{{cos(x)=ADJ/HYP=A/H}}}