Question 894608
{{{log(5,16)}}}
={{{log(5,2^4)}}}
={{{4log(5,2)}}}
={{{4(1/log(2,5))}}}
={{{4/log(2,5)}}}
={{{4/log(2^3,5^3)}}}
={{{4/log(8,5^3)}}}
={{{4/3log(8,5)}}}, where {{{log(8,5)=a}}}
={{{4/3(a)}}}
={{{4/3a}}}