Question 75919
Factor:
{{{1000x^3+1}}}  Do you recognise this as the sum of two cubes?
{{{(10x)^2+(1)^3}}} 
You can factor the sum of two cubes as follows:
{{{A^3+B^3 = (A+B)(A^2-AB+B^2)}}} Applying this to your problem, where A = 10x and B = 1, you get:
{{{(10x+1)((10x)^2-(10x)(1)+(1)^2)}}} Simplify.
{{{(10x+1)(100x^2-10x+1)}}}