Question 898520

Please help me solve this problem: Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 11 mi long. One hiker walks 0.5 mph faster than the other hiker. How fast did each hiker walk if they meet in 2 h?
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Let speed of slower hiker be S
Then speed of faster hiker is: S + .5
Since their respective distances sum to 11 miles, and they met in 2 hours, then we get: 
2S + 2(S + .5) = 11
2S + 2S + 1 = 11
4S = 11 – 1
4S = 10
S, or speed of slower hiker = {{{10/4}}}, or {{{highlight_green(highlight_green(2.5))}}} mph
Faster hiker’s speed: 2.5 + .5, or {{{highlight_green(highlight_green(3))}}} mph
You can do the check!! 

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