<PRE><B>Question 898572</B>
let first leg be x
second was half the length of the first leg,= x/2
 the third leg was two-thirds of the length of the second leg.(2/3)(x/2)
 and the last leg was twice the length of the second leg 2*(x/2) =x


if the total distance was 153km 

x+ x/2 + x/3 + x= 153 
multiply y 
6x+3x+2x+6x= 6*153

17x= 6*153

x=54 the first leg

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