<PRE><B>Question 898513</B>
y(y-12)-15=y(y+5)-3(y+5) 
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y^2 - 12y - 15 = y^2 + 5y - 3y - 15
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-12y - 15 = 2y - 15
14y = 0
y = 0
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Cheers,
Stan H.
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