Question 898135
{{{AB=2x}}}
{{{BC=x}}}
Using the Pythagorean theorem,
{{{AB^2+BC^2=AC^2}}}
{{{(2x)^2+x^2=AC^2}}}
{{{AC^2=5x^2}}}
{{{AC=sqrt(5)x}}}
Then,
{{{sin(C)=(2x)/(sqrt(5)x)=2/sqrt(5)=(2/5)sqrt(5)}}}
{{{A=63.4}}}
{{{sin(A)=(x)/(sqrt(5)x)=sqrt(5)/5}}}
{{{B=26.6}}}