Question 898017
Can someone help me graph this question and find the domain and range please?
 f(x)={(x-2)^2-1) x<4
 (3/2)x-3 x>=4
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Since x is defined for x<4 and for x>=4, Domain is All Real Numbers.
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On the Domain x < 4,
Range starts at (4-2)^2-1 = 3 and goes to +oo as x goes to -oo
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On the Domian x >= 4,
Range starts at (3/2)4-3 = 3 and goes to +oo as x goes to +oo
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Cheers,
Stan H.
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