Question 898079
If the measures are {{{angle}} and {{{complement}}}, in degrees,
{{{angle+complement=90}}} <--> {{{complement=90-angle}}}
The problem says that {{{angle=5*complement}}} , so
{{{angle=5*(90-angle)}}}
{{{angle=5*90-5*angle)}}}
{{{angle=450-5*angle)}}}
{{{angle+5*angle=450)}}}
{{{6*angle=450)}}
{{{angle=450/6)}}
{{{highlight(angle=75)}}}
The original angle measures {{{highlight(75^o)}}} ,
and that is 5 times the measure of its complement,
which is {{{90^o-75^o=15^o}}} .