Question 897775
logically it would appear that the plane with 6 engines will have a probability of success greater than a plane with 4 engines.


let's see if that's true.
this appears to be a binomial probability where:


p(x) = C(n,x) * p^x * q^(n-x)


p is the probability of success which is equal to .65
q is the probability of failure which is equal to .35



for the 4 engine plane, we want the probability that 2 or more engines are operating successfully.


 this would be equal to p(2) + p(3) + p(4)


for the 6 engine plane, we want the probability that 3 or more enginers are operating successfully.


this would be equal to p(3) + p(4) + p(5) + p(6).


the complete probabilities are shown n the following tables calculated by using excel.


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