Question 897786

let's number be {{{x}}}
the sum of twice a number and {{{13}}} is {{{2x+13}}} 

and the difference between {{{-41}}} and the number is {{{-41-x}}}

if {{{2x+13}}}  less than {{{ -41-x}}}, we have



{{{2x+13< -41-x}}} ....solve for {{{x}}}

{{{2x+x< -41-13}}}

{{{3x< -54}}}

{{{x< -54/3}}}

{{{x< -18}}}

so, solution is all real numbers {{{x< -18}}},

{ {{{-19}}},{{{-20}}},{{{-21}}}.....}


check for {{{x=-19}}} first on less than {{{-18}}}:

{{{2x+13< -41-x}}}

{{{2*(-19)+13< -41-(-19)}}}

{{{-38+13< -41+19}}}

{{{-25< -22}}} which is true